如果链表中得变量多了怎么办？

  struct Test t1 = {1,NULL};
     struct Test t2 = {2,NULL};
     struct Test t3 = {3,NULL};
     struct Test t4 = {4,NULL};

    t1.next = &t2;
    t2.next = &t3;
    t3.next = &t4;

那就不能用这种办法了。

printf("%d %d %d %d\n",t1.data,t1.next->data,t1.next->next->data,t1.next->next->next->data);

我们可以用函数遍历。

void printLink(struct Test *head)
{
    while(head != NULL){
       if(head != NULL){
         printf("%d\n",head->data);
         head = head->next;
    }else{
         break;
     }
  }
    return ;
}

整篇代码

#include <stdio.h>

struct Test
{
    int data;
    struct Test *next;
};

void printLink(struct Test *head)
{
    while(head != NULL){
       if(head != NULL){
         printf("%d\n",head->data);
         head = head->next;
    }else{
         break;
     }
  }
    return ;
}
int main()
{
   int i;
   int array[3] = {1,2,3};
     for(i=0;i<sizeof(array)/sizeof(array[0]);i++){
        printf("%d\n",array[i]);

   }

     struct Test t1 = {1,NULL};
     struct Test t2 = {2,NULL};
     struct Test t3 = {3,NULL};
     struct Test t4 = {4,NULL};

    t1.next = &t2;
    t2.next = &t3;
    t3.next = &t4;
      printf("=====use t1 print three num=====\n");
    // printf("%d %d %d %d\n",t1.data,t1.next->data,t1.next->next->data,t1.next->next->next->data);
    printLink(&t1);
  return 0;
}
                                                                                                                                  

用函数遍历的运行结果